Conversion Factors and the Specific Gravity of Minerals
Aug 18, 2020#0183;#32;A gold ore with a concentration of g / cm 3 has a density of g / cm 3. What is the volume of gold (D = g / cm 3)in 100 cm 3 of the ore? Answer. The volume of 100 g of ore is [text{V} = dfrac{m}{D} = dfrac{100 g}{ g/cm^3} = text{ cm}^3] The mass of gold in this volume is